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Bash – Variable indirection – Using variable contents as a(nother) variable name

This was a tricky action. Assume I have a list of variables, obtained by an external source: var1=a var2=b var3=c I cannot use loop and in it the phrase ${var$i} (where i is the integer counter). It just doesn’t work. I used this instead to assign the values to an array: var[$i]=$(eval echo "${var${i}}") That…